Odpowiedź:
Wyjaśnienie:
Zad.1
Dane: Szukane:
HCl mr HCl=?
C= 20%
AgNO₃
mr = 150g
Cp=2%
ms = mr*Cp/100%
ms = 150g*2%/100%
ms = 3g AgNO₃
AgNO₃ + HCl = AgCl + HNO₃
170g 36,5g
170g AgNO₃.............36,5g HCl
3g AgNO₃...................x
x = 0,64g HCl
mr = ms*100%/Cp
mr = 0,64g*100%/20%
mr = 3,2g roztworu HCl
Zad.2
BaCl₂ + K₂CrO₄ = BaCrO₄ + 2KCl
208g 194g 253g
208g BaCl₂.............253g BaCrO₄
x g..............................100g
x = 82,2g BaCl₂
194g K₂CrO₄.............253g BaCrO₄
x = 76,7g K₂CrO₄
Zad. 3
x = % strat
98g = 120g - x*120g
120x = 22
x = 0,18
x = 18%
18% strat czyli wydajność krystalizacji 100% - 18% = 82%
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Odpowiedź:
Wyjaśnienie:
Zad.1
Dane: Szukane:
HCl mr HCl=?
C= 20%
AgNO₃
mr = 150g
Cp=2%
ms = mr*Cp/100%
ms = 150g*2%/100%
ms = 3g AgNO₃
AgNO₃ + HCl = AgCl + HNO₃
170g 36,5g
170g AgNO₃.............36,5g HCl
3g AgNO₃...................x
x = 0,64g HCl
mr = ms*100%/Cp
mr = 0,64g*100%/20%
mr = 3,2g roztworu HCl
Zad.2
BaCl₂ + K₂CrO₄ = BaCrO₄ + 2KCl
208g 194g 253g
208g BaCl₂.............253g BaCrO₄
x g..............................100g
x = 82,2g BaCl₂
194g K₂CrO₄.............253g BaCrO₄
x g..............................100g
x = 76,7g K₂CrO₄
Zad. 3
x = % strat
98g = 120g - x*120g
120x = 22
x = 0,18
x = 18%
18% strat czyli wydajność krystalizacji 100% - 18% = 82%