[tex]Dane:\\ m=0,5kg\\ Q=2250J\\ C=450\frac{J}{kg\cdot^0C}\\ Szukane:\\ \Delta T=?\\ Rozwiazanie:\\ \\ Q=Cm\Delta T\\ \\ \Delta T=\dfrac{Q}{mC}\\ \\ \\ \Delta T=\dfrac{4500}{0,5\cdot450}\\ \\ \Delta T=20^0C[/tex]
Temperatura spadnie o 20 stopni
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[tex]Dane:\\ m=0,5kg\\ Q=2250J\\ C=450\frac{J}{kg\cdot^0C}\\ Szukane:\\ \Delta T=?\\ Rozwiazanie:\\ \\ Q=Cm\Delta T\\ \\ \Delta T=\dfrac{Q}{mC}\\ \\ \\ \Delta T=\dfrac{4500}{0,5\cdot450}\\ \\ \Delta T=20^0C[/tex]
Temperatura spadnie o 20 stopni