Zadanie 7
884 u 870 u
(C17H33COO)3C3H5+Al(OH)3--->(C17H33COO)3Al+C3H5(OH)3
100 g xg
884 u---870 u
100 g---xg
x=98,42 g
Zadanie 8
octan pentylu- CH3COOC5H11
mCH3COOC5H11=7*12 u+14*1u+2*16 u=130 u
84 u---x%
130 u---100%
x=64,62%C
maślan pentylu- C3H7COOC5H11
mC3H7COOC5H11=9*12 u+18*1 u+2*16 u=158 u
108 u---x%
158 u---100%
x=68,35%C
mrówczan pentylu- HCOOC5H11
mHCOOC5H11=6*12 u+12*1 u+2*16 u=116 u
72 u---x%
116 u---100%
x=62,07%C
maślan etylu- C3H7COOC2H5
mC3H7COOC2H5=6*12 u+12*1 u+2*16 u=116 u
octan etylu- CH3COOC2H5
mCH3COOC2H5=4*12 u+8*1 u+2*16 u=88 u
48 u---x%
88 u---100%
x=54,55%C
Odp: Największą zawartość procentową węgla ma maślan pentylu
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Verified answer
Zadanie 7
884 u 870 u
(C17H33COO)3C3H5+Al(OH)3--->(C17H33COO)3Al+C3H5(OH)3
100 g xg
884 u---870 u
100 g---xg
x=98,42 g
Zadanie 8
octan pentylu- CH3COOC5H11
mCH3COOC5H11=7*12 u+14*1u+2*16 u=130 u
84 u---x%
130 u---100%
x=64,62%C
maślan pentylu- C3H7COOC5H11
mC3H7COOC5H11=9*12 u+18*1 u+2*16 u=158 u
108 u---x%
158 u---100%
x=68,35%C
mrówczan pentylu- HCOOC5H11
mHCOOC5H11=6*12 u+12*1 u+2*16 u=116 u
72 u---x%
116 u---100%
x=62,07%C
maślan etylu- C3H7COOC2H5
mC3H7COOC2H5=6*12 u+12*1 u+2*16 u=116 u
72 u---x%
116 u---100%
x=62,07%C
octan etylu- CH3COOC2H5
mCH3COOC2H5=4*12 u+8*1 u+2*16 u=88 u
48 u---x%
88 u---100%
x=54,55%C
Odp: Największą zawartość procentową węgla ma maślan pentylu