[tex](x-\sqrt{3})(x^2+\sqrt{3}x+3)+(x+\sqrt{3})(x^2-\sqrt{3}x+3)=\\\\=x^3+\sqrt{3}x^2+3x-\sqrt{3}x^2-3x-3\sqrt{3}+x^3-\sqrt{3}x^2+3x+\sqrt{3}x^2-3x+3\sqrt{3}=\\\\=x^3+x^3=2x^3\\\\Obliczamy\ \ warto\'s\'c\ \ otrzymanego\ \ wyra\.zenia\ \ dla\ \ x=\frac{\sqrt{3}}{2}\\\\2x^3=2\cdot(\frac{\sqrt{3}}{2})^3=2\cdot\frac{(\sqrt{3})^3}{2^3}=2\cdot\frac{\sqrt{27}}{8}=2\cdot\frac{\sqrt{9\cdot3}}{8}=2\cdot\frac{\sqrt{9}\cdot\sqrt{3}}{8}=\not2^1\cdot\frac{3\sqrt{3}}{\not8_{4}}=\frac{3\sqrt{3}}{4}[/tex]
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[tex](x-\sqrt{3})(x^2+\sqrt{3}x+3)+(x+\sqrt{3})(x^2-\sqrt{3}x+3)=\\\\=x^3+\sqrt{3}x^2+3x-\sqrt{3}x^2-3x-3\sqrt{3}+x^3-\sqrt{3}x^2+3x+\sqrt{3}x^2-3x+3\sqrt{3}=\\\\=x^3+x^3=2x^3\\\\Obliczamy\ \ warto\'s\'c\ \ otrzymanego\ \ wyra\.zenia\ \ dla\ \ x=\frac{\sqrt{3}}{2}\\\\2x^3=2\cdot(\frac{\sqrt{3}}{2})^3=2\cdot\frac{(\sqrt{3})^3}{2^3}=2\cdot\frac{\sqrt{27}}{8}=2\cdot\frac{\sqrt{9\cdot3}}{8}=2\cdot\frac{\sqrt{9}\cdot\sqrt{3}}{8}=\not2^1\cdot\frac{3\sqrt{3}}{\not8_{4}}=\frac{3\sqrt{3}}{4}[/tex]