Question

proszę o pomoc z chemii z DWÓCH zadań (wyślę w zał. I daje naj) ​

Answer 1

Verified answer

//Zadanie 9//

MS = 32g/mol

MH = 1g/mol

MH2S = 34g/mol

mS = 120g

32gS — 34gH2S

120gS — x[gH2S]

______________

x= (120*34):32 = 127,5g

//Zadanie 10//

• H2SO4

mH2 = 2u

mS = 32u

mO4 = 64u

mH2SO4 = 98u

%H = (2u * 100%):98u = 2%

%S = (32u *100%):98u = 32,7%

%O = 100% – (2% + 32,7%) = 65,3%

• H3PO4

mH3 = 3u

mP = 31u

mO = 64u

mH3PO4 = 98

%H = (3u * 100%):98u = 3%

%P = (31u * 100%):98u = 31,6%

%O = 100% - (3% + 31,6%) = 65,4%

Answer 2

Zadanie 9

     32u   34u

H2+S--->H2S

     120g   xg

32u---34u

120g---xg

x=127,5g

Zadanie 10

kwas siarkowy(VI)- H2SO4

mH2SO4=2*1u+32u+4*16u=98u

2u---x%

98u---100%

x=2,04%H

32u---x%

98u---100%

x=32,65%S

100%-(2,04%+32,65%)=65,31%O

kwas fosforowy(V)- H3PO4

mH3PO4=3*1u+31u+4*16u=98u

3u---x%

98u---100%

x=3,06%H

31u---x%

98u---100%

x=31,63%P

100%-(3,06%+31,63%)=65,31%O