Odpowiedź:
6.
a)
a = 13 cm
d2 = 24 cm
x = 0.5d2 = 12 cm
y = 0,5 d1
[tex]13^2 = x^2 + y^2\\13^2 = 12^2 + y^2\\169 = 144 + y^2\\y^2 = 169 - 144 = 25 \\ y = 5 cm[/tex]
P = 5 * 24 = [tex]120 cm^2[/tex]
h - wysokość
h = [tex]\frac{120}{13}[/tex] cm
b)
a = 6 cm
x = 0,5 d1
y = 0,5d2
x/6 = 1/3 /* 6
x = 6/3 = 2 cm
[tex]6^2 = 2^2 + y^2\\36 = 4 + y^2\\y^2 = 36 - 4 = 32 \\y = \sqrt{32} = \sqrt{2 * 16} = 4\sqrt{2}[/tex] cm
d2 = 2y
P = 2 * [tex]8\sqrt{2} = 16\sqrt{2} cm^2[/tex]
h = [tex]\frac{16\sqrt{2} }{6} = \frac{8}{3} \sqrt{2} cm[/tex]
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Odpowiedź:
6.
a)
a = 13 cm
d2 = 24 cm
x = 0.5d2 = 12 cm
y = 0,5 d1
[tex]13^2 = x^2 + y^2\\13^2 = 12^2 + y^2\\169 = 144 + y^2\\y^2 = 169 - 144 = 25 \\ y = 5 cm[/tex]
P = 5 * 24 = [tex]120 cm^2[/tex]
h - wysokość
h = [tex]\frac{120}{13}[/tex] cm
b)
a = 6 cm
x = 0,5 d1
y = 0,5d2
x/6 = 1/3 /* 6
x = 6/3 = 2 cm
[tex]6^2 = 2^2 + y^2\\36 = 4 + y^2\\y^2 = 36 - 4 = 32 \\y = \sqrt{32} = \sqrt{2 * 16} = 4\sqrt{2}[/tex] cm
d2 = 2y
P = 2 * [tex]8\sqrt{2} = 16\sqrt{2} cm^2[/tex]
h = [tex]\frac{16\sqrt{2} }{6} = \frac{8}{3} \sqrt{2} cm[/tex]