Odpowiedź:
a) P = 0,5*6*10*sin 30°° = 30*0,5 = 15 j²
b ) P = 0,5*10*12*sim 120° = 60* sin ( 90° + 30°) = 60*cos 30° =
= 60*0,5√3 = 30√3 j²
c) I ∡ BAC I = 180° - 135° = 45°
P = 0,5*4√3*√3*sin 45° = 6*0,5√2 = 3√2 j²
d)
I ∡ BAC I = 180° -2^15° = 150°
P = 0,5*3√2*3√2*sin 150° = 9*sin ( 90° + 60° ) = 9*cos 60° = 9*0,5 = 4,5 j²
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Odpowiedź:
a) P = 0,5*6*10*sin 30°° = 30*0,5 = 15 j²
b ) P = 0,5*10*12*sim 120° = 60* sin ( 90° + 30°) = 60*cos 30° =
= 60*0,5√3 = 30√3 j²
c) I ∡ BAC I = 180° - 135° = 45°
P = 0,5*4√3*√3*sin 45° = 6*0,5√2 = 3√2 j²
d)
I ∡ BAC I = 180° -2^15° = 150°
P = 0,5*3√2*3√2*sin 150° = 9*sin ( 90° + 60° ) = 9*cos 60° = 9*0,5 = 4,5 j²
===============================================================
Szczegółowe wyjaśnienie: