Question

Proszę o pomoc całe zadanie 6
Na teraz (Rozwinięte!)

Answer 1

Verified answer

Odpowiedź:

a)

[tex](9^5*9^9):(9^8*9^4)=9^{5+9}:9^{8+4}=9^{14}:9^{12}=9^{14-12}=9^2=81[/tex]

b)

[tex](7^3*7^2:7^5)*\frac{7^4}{7^2}=7^{3+2-5}*7^4:7^2=7^0*7^{4-2}=1*7^2=1*49=49[/tex]

c)

[tex]\frac{8^3:8^0*8^{11}}{8^5*8^7} =\frac{8^{3-0+11}}{8^{5+7}}=\frac{8^{14}}{8^{12}}=8^{14}:8^{12}=8^{14-12}=8^2=64[/tex]

d)

[tex]100*10^2=100*100=10 000[/tex]

e)

[tex]1000*10^4=10^3*10^4=10^{3+4}=10^7=10000000[/tex]

f)

[tex]0,01*10^4=0,01*10000=100[/tex]

Szczegółowe wyjaśnienie:

Answer 2

Odpowiedź:

a)

(9^5*9^9):(9^8*9^4)=9^{5+9}:9^{8+4}=9^{14}:9^{12}=9^{14-12}=9^2=81(9

5

∗9

9

):(9

8

∗9

4

)=9

5+9

:9

8+4

=9

14

:9

12

=9

14−12

=9

2

=81

b)

(7^3*7^2:7^5)*\frac{7^4}{7^2}=7^{3+2-5}*7^4:7^2=7^0*7^{4-2}=1*7^2=1*49=49(7

3

∗7

2

:7

5

)∗

7

2

7

4

=7

3+2−5

∗7

4

:7

2

=7

0

∗7

4−2

=1∗7

2

=1∗49=49

c)

\frac{8^3:8^0*8^{11}}{8^5*8^7} =\frac{8^{3-0+11}}{8^{5+7}}=\frac{8^{14}}{8^{12}}=8^{14}:8^{12}=8^{14-12}=8^2=64

8

5

∗8

7

8

3

:8

0

∗8

11

=

8

5+7

8

3−0+11

=

8

12

8

14

=8

14

:8

12

=8

14−12

=8

2

=64

d)

100*10^2=100*100=10 000100∗10

2

=100∗100=10000

e)

1000*10^4=10^3*10^4=10^{3+4}=10^7=100000001000∗10

4

=10

3

∗10

4

=10

3+4

=10

7

=10000000

f)

0,01*10^4=0,01*10000=1000,01∗10

4

=0,01∗10000=100