[tex]\displaystyle|\Omega|=\binom{10}{2}=\dfrac{10!}{2!8!}=\dfrac{9\cdot10}{2}=45\\|A|=2\cdot8+1=17[/tex]
[tex]P(A)=\dfrac{17}{45}[/tex]
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[tex]\displaystyle|\Omega|=\binom{10}{2}=\dfrac{10!}{2!8!}=\dfrac{9\cdot10}{2}=45\\|A|=2\cdot8+1=17[/tex]
[tex]P(A)=\dfrac{17}{45}[/tex]