Question

pppp tolong dong pppp​

Answer 1

Penjelasan dengan langkah-langkah:

1. d = 10 cm → r = 5 cm

t = 20 cm

Luas permukaan ce*len*gan = πd(r + t)

= 3,14 × 10 × (5 + 20)

= 31,4 × 25

= 785 cm²

Luas 100 cel*eng*an = 100 × 785

= 78.500 cm²

= 7,85 m²

Biaya minimal = 7,85 × 8.000 + 100 × 4.000

= 62.800 + 400.000

= Rp. 462.800,00 ✔

2. Luas kaleng = πr(r + 2t)

kaleng 1 : d = 7 cm → r = 3,5 cm , t = 10 cm

Luas kaleng 1 = 7 × 22/7 × 3,5 × (3,5 + 2 × 10)

= 22 × 3,5 × 23,5

= 77 × 23,5

= 1.809,5 cm²

kaleng 2 : d = 10 → r = 5 cm , t = 12 cm

Luas kaleng 2 = 6 × 3,14 × 5 × (5 + 2×12)

= 94,2 × 29

= 2.731,8 cm²

kaleng 3 : d = 14 cm → r = 7 cm, t = 20 cm

Luas kaleng 3 = 7 × 22/7 × 7 × (7 + 2×20)

= 154 × 47

= 7.238 cm²

Luas alumunium yang dibutuhkan = 1.809,5 + 2.731,8 + 7.238 = 11.779,3 cm²

= 117,793 dm²

= 1,17793 m²

biaya minimum = 1,17793 × 20.000

= Rp. 23.558,6 ✔

Answer 2

Penjelasan dengan langkah-langkah:

1.

Diketahui :

ukuran c3l3ng4n :

diameter = 10 cm.

tinggi = 20 cm.

Penyelesaian :

2.