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NaOH
Cm=0,01mol/dm3
v=?
H2S04
v=50cm3=0,05dm3
Cm=0,01mol/dm3
n=v*Cm
n=0,0005mola
2moleNaOH---- 1mol H2SO4
x------- 0,0005mola H2SO4
x=0,001 mola NaOH
wiec podstawiamy do wzoru
v=n/Cm
vNaOH=0,001/0,01=1dm3
Pozdrawiam, licze na najlepsze roziwazanie;)