[tex]a)\ \ 2\frac{1}{2}:5-\frac{1}{3}=\frac{\not5^1}{2}\cdot\frac{1}{\not5_{1}}-\frac{1}{3}=\frac{1}{2}-\frac{1}{3}=\frac{3}{6}-\frac{2}{6}=\frac{1}{6}\\\\b)\ \ (3\frac{1}{3}+\frac{5}{9}):7=(3\frac{3}{9}+\frac{5}{9}):7=3\frac{8}{9}:7=\frac{\not35^5}{9}\cdot\frac{1}{\not7_{1}}=\frac{5}{9}\\\\c)\ \ (1\frac{4}{7}-1\frac{1}{3}):10=(1\frac{12}{21}-1\frac{7}{21}):10=\frac{\not5^1}{21}\cdot\frac{1}{\not10_{2}}=\frac{1}{21}\cdot\frac{1}{2}=\frac{1}{42}[/tex]
[tex]d)\ \ (5\frac{1}{5}-2\frac{3}{4}):2^2=(5\frac{4}{20}-2\frac{15}{20}):4=(4\frac{24}{20}-2\frac{15}{20}):4=2\frac{9}{20}:4=\frac{49}{20}\cdot\frac{1}{4}=\frac{49}{80}[/tex]
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[tex]a)\ \ 2\frac{1}{2}:5-\frac{1}{3}=\frac{\not5^1}{2}\cdot\frac{1}{\not5_{1}}-\frac{1}{3}=\frac{1}{2}-\frac{1}{3}=\frac{3}{6}-\frac{2}{6}=\frac{1}{6}\\\\b)\ \ (3\frac{1}{3}+\frac{5}{9}):7=(3\frac{3}{9}+\frac{5}{9}):7=3\frac{8}{9}:7=\frac{\not35^5}{9}\cdot\frac{1}{\not7_{1}}=\frac{5}{9}\\\\c)\ \ (1\frac{4}{7}-1\frac{1}{3}):10=(1\frac{12}{21}-1\frac{7}{21}):10=\frac{\not5^1}{21}\cdot\frac{1}{\not10_{2}}=\frac{1}{21}\cdot\frac{1}{2}=\frac{1}{42}[/tex]
[tex]d)\ \ (5\frac{1}{5}-2\frac{3}{4}):2^2=(5\frac{4}{20}-2\frac{15}{20}):4=(4\frac{24}{20}-2\frac{15}{20}):4=2\frac{9}{20}:4=\frac{49}{20}\cdot\frac{1}{4}=\frac{49}{80}[/tex]