Question

Potrzebuje pomocy z tym co na zdjęciu.

Answer 1

Odpowiedź:

a)  [tex]\frac{3}{4}+\frac{1}{4} *5 =\frac{3}{4}+\frac{5}{4} =\frac{3+5}{4}=\frac{8}{4}=2[/tex]

b) [tex]1\frac{5}{6}-\frac{1}{6}*1\frac{1}{2}= 1\frac{5}{6}-\frac{1}{6}*\frac{3}{2}= 1\frac{5}{6}-\frac{1}{4}= \frac{11}{6}-\frac{1}{4}=\frac{22}{12}-\frac{3}{12}=\frac{19}{12} =1\frac{7}{12}[/tex]

c) [tex](1\frac{3}{8} +2\frac{5}{6} )*12=(\frac{11}{8} +\frac{17}{6} )*12=(\frac{33}{24} +\frac{68}{24} )*12=\frac{101}{24} *12=\frac{101}{2} =50\frac{1}{2}[/tex]

d) [tex]1\frac{1}{3}*(3+2*\frac{3}{4} ) =\frac{4}{3}*(3 +\frac{2}{1} *\frac{3}{4} ) =\frac{4}{3}*(\frac{6}{2} +\frac{3}{2} ) =\frac{4}{3}*\frac{9}{2}=\frac{2}{1}*\frac{3}{1}=6[/tex]

e) [tex]6\frac{1}{6}:\frac{1}{6} -2\frac{1}{4}:2 =\frac{37}{6}*6 -\frac{9}{4}*\frac{1}{2} =37-\frac{9}{8}=37-1\frac{1}{8}=35\frac{7}{8}[/tex]

f)

[tex](4\frac{1}{6}-3\frac{5}{7}):19=(4\frac{1*7}{6*7}-3\frac{5*6}{7*6}):19=(4\frac{7}{42}-3\frac{30}{42}):19=(3\frac{49}{42}-3\frac{30}{42})*\frac{1}{19} =\frac{19}{42} *\frac{1}{19} =\frac{1}{42}[/tex]