[tex]a)\ \ \sqrt{81}+5=9+5=14\\\\\\b)\ \ \sqrt[3]{1000}-100=10-100-90\\\\\\c)\ \ 4\sqrt{\frac{1}{121}}=4\cdot\frac{1}{11}=\frac{4}{11}\\\\\\d)\ \ \frac{\sqrt[3]{-27}}{18}=\frac{-3}{18}=-\frac{1}{6}\\\\\\e)\ \ 2\sqrt[3]{125}-3=2\cdot5-3=10-3=7\\\\\\f)\ \ \frac{6}{\sqrt{144}}+1=\frac{6}{12}+1=\frac{1}{2}+1=1\frac{1}{2}\\\\\\g)\ \ \frac{3\sqrt[3]{-8}}{4}-5=\frac{3\cdot(-2)}{4}-5=\frac{-6}{4}-5=-\frac{3}{2}-5=-1\frac{1}{2}-5=-6\frac{1}{2}[/tex]
[tex]h)\ \ \sqrt{16}+\sqrt[3]{125}=4+5=9\\\\\\i)\ \ \sqrt{169}+\sqrt{36}-\sqrt{49}=13+6-7=19-7=12\\\\\\j)\ \ \sqrt[3]{1000}\cdot\sqrt{9}=10\cdot3=30\\\\\\k)\ \ \sqrt{900}:\sqrt[3]{27}+\sqrt{49}=30:3+7=10+7=17\\\\\\l)\ \ 3\sqrt{36}+5\sqrt[3]{-64}=3\cdot6+5\cdot(-4)=18-20=-2[/tex]
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[tex]a)\ \ \sqrt{81}+5=9+5=14\\\\\\b)\ \ \sqrt[3]{1000}-100=10-100-90\\\\\\c)\ \ 4\sqrt{\frac{1}{121}}=4\cdot\frac{1}{11}=\frac{4}{11}\\\\\\d)\ \ \frac{\sqrt[3]{-27}}{18}=\frac{-3}{18}=-\frac{1}{6}\\\\\\e)\ \ 2\sqrt[3]{125}-3=2\cdot5-3=10-3=7\\\\\\f)\ \ \frac{6}{\sqrt{144}}+1=\frac{6}{12}+1=\frac{1}{2}+1=1\frac{1}{2}\\\\\\g)\ \ \frac{3\sqrt[3]{-8}}{4}-5=\frac{3\cdot(-2)}{4}-5=\frac{-6}{4}-5=-\frac{3}{2}-5=-1\frac{1}{2}-5=-6\frac{1}{2}[/tex]
[tex]h)\ \ \sqrt{16}+\sqrt[3]{125}=4+5=9\\\\\\i)\ \ \sqrt{169}+\sqrt{36}-\sqrt{49}=13+6-7=19-7=12\\\\\\j)\ \ \sqrt[3]{1000}\cdot\sqrt{9}=10\cdot3=30\\\\\\k)\ \ \sqrt{900}:\sqrt[3]{27}+\sqrt{49}=30:3+7=10+7=17\\\\\\l)\ \ 3\sqrt{36}+5\sqrt[3]{-64}=3\cdot6+5\cdot(-4)=18-20=-2[/tex]