Odpowiedź:
68.
a)MNa2O= 2*22,990g/mol + 15,999g/mol= 61,9g/mol
b)M Mg(OH)2 =24,305g/mol+ 2*15,999g/mol +2*1,008g/mol= 58,3g/mol
c)M H2CO3 = 2*1.008g/mol + 12,011g/mol + 3*15,999g/mol= 62,0g/mol
69.
stosunek masowy
a) N2O
N : O= 2*14u :16u =28 u :16u=7:4
b) NO
N : O= 14u : 16u = 7: 8
c)N2O3
N: O= 2*14u : 3*16u =28u : 48u=7: 12
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Odpowiedź:
68.
a)MNa2O= 2*22,990g/mol + 15,999g/mol= 61,9g/mol
b)M Mg(OH)2 =24,305g/mol+ 2*15,999g/mol +2*1,008g/mol= 58,3g/mol
c)M H2CO3 = 2*1.008g/mol + 12,011g/mol + 3*15,999g/mol= 62,0g/mol
69.
stosunek masowy
a) N2O
N : O= 2*14u :16u =28 u :16u=7:4
b) NO
N : O= 14u : 16u = 7: 8
c)N2O3
N: O= 2*14u : 3*16u =28u : 48u=7: 12