Odpowiedź:
[tex]a_1 = - 4 \\r = 3[/tex]
więc
[tex]a_n = a_1 + (n - 1)*r = - 4 + ( n - 1)*3 = 3 n - 7\\oraz\\a_{n+1} = 3 n - 7 + r = 3 n - 7 + 3 = 3 n - 4\\a_{n+2} = 3 n - 4 + r = 3 n - 4 + 3 = 3 n - 1\\a_{n+3} = 3 n - 1 + r = 3 n - 1 + 2 = 3 n + 2[/tex]
zatem
[tex]\frac{a_n + a_{n+1} + a_{n+2} + a_{n + 3}}{4} + \frac{(3n -7) + (3 n - 4) + ( 3n - 1) + (3 n +2}{4} = 24,5/ * 4[/tex]
12 n - 10 = 98
12 n = 108 / : 12
n = 9
Odp. Te wyrazy, to: [tex]a_9, a_{10} , a_{11}, a_{12}[/tex]
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[tex]a_9 = 20, a_{10} = 23, a_{11} = 26, a_{12} = 29[/tex]
Szczegółowe wyjaśnienie:
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Odpowiedź:
[tex]a_1 = - 4 \\r = 3[/tex]
więc
[tex]a_n = a_1 + (n - 1)*r = - 4 + ( n - 1)*3 = 3 n - 7\\oraz\\a_{n+1} = 3 n - 7 + r = 3 n - 7 + 3 = 3 n - 4\\a_{n+2} = 3 n - 4 + r = 3 n - 4 + 3 = 3 n - 1\\a_{n+3} = 3 n - 1 + r = 3 n - 1 + 2 = 3 n + 2[/tex]
zatem
[tex]\frac{a_n + a_{n+1} + a_{n+2} + a_{n + 3}}{4} + \frac{(3n -7) + (3 n - 4) + ( 3n - 1) + (3 n +2}{4} = 24,5/ * 4[/tex]
12 n - 10 = 98
12 n = 108 / : 12
n = 9
Odp. Te wyrazy, to: [tex]a_9, a_{10} , a_{11}, a_{12}[/tex]
===============================
[tex]a_9 = 20, a_{10} = 23, a_{11} = 26, a_{12} = 29[/tex]
Szczegółowe wyjaśnienie: