[tex]2\frac{1}{3}+\frac{3}{4}:\frac{1}{2}=2\frac{1}{3}+\frac{3}{\not4_{2}}\cdot\not2^1=2\frac{1}{3}+\frac{3}{2}=2\frac{1}{3}+1\frac{1}{2}=2\frac{2}{6}+1\frac{3}{6}=3\frac{5}{6}[/tex]
Odpowiedź:
[tex]2 \frac{1}{3} + \frac{3}{4} \div \frac{1}{2} = \frac{7}{3} + \frac{3}{4} \times \frac{2}{1} = \frac{7}{3} + \frac{6}{4} = \frac{28}{12} + \frac{18}{12} = \frac{46}{12} = 3 \frac{10}{12} = 3 \frac{5}{6} [/tex]
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Verified answer
[tex]2\frac{1}{3}+\frac{3}{4}:\frac{1}{2}=2\frac{1}{3}+\frac{3}{\not4_{2}}\cdot\not2^1=2\frac{1}{3}+\frac{3}{2}=2\frac{1}{3}+1\frac{1}{2}=2\frac{2}{6}+1\frac{3}{6}=3\frac{5}{6}[/tex]
Odpowiedź:
[tex]2 \frac{1}{3} + \frac{3}{4} \div \frac{1}{2} = \frac{7}{3} + \frac{3}{4} \times \frac{2}{1} = \frac{7}{3} + \frac{6}{4} = \frac{28}{12} + \frac{18}{12} = \frac{46}{12} = 3 \frac{10}{12} = 3 \frac{5}{6} [/tex]