Potrzebuję na teraz:
Jaki procent masowy stanowi azot w cząsteczce tlenku azoty(I)N2O?
M N2O = 14*2 + 16 = 28 + 16 = 44 u % N = 28/44 * 100% = 64 %
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M N2O = 14*2 + 16 = 28 + 16 = 44 u
% N = 28/44 * 100% = 64 %