Odpowiedź:
[tex]\huge\boxed {~~y=\dfrac{8}{35} x^{2} +1\dfrac{29}{35} x-4\dfrac{4}{7} ~~}~~\Rightarrow[/tex] wzór szukanej funkcji kwadratowej
Szczegółowe wyjaśnienie:
Dane z treści zadania:
Szukana:
Obliczamy :
[tex]y=a(x-x_{1} )(x-x_{2} )~~\land ~~x_{1} =-10~~\land~~x_{2} =2\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\Downarrow \\\\y=a(x-(-10) )(x-2)\\\\y=a(x+10 )(x-2)~~\land ~~A\in y~~\land ~~A(-3,-8)\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\Downarrow \\\\-8=a(-3+10)(-3-2)\\\\a\cdot 7\cdot (-5)=-8\\\\-35a=-8~~\mid \div (-35)\\\\\huge\boxed {~~a=\dfrac{8}{35} ~~}\\\\\\y=a(x+10)(x-2)~~\land ~~a=\dfrac{8}{35} \\\\~~~~~~~~~~~~~~~\Downarrow \\\\y=\frac{8}{35} (x^{2} -2x+10x-20)\\\\y=\frac{8}{35} (x^{2} +8x-20)\\[/tex]
[tex]y=\dfrac{8}{35} x^{2} +\dfrac{8}{35} \cdot 8x-\dfrac{8}{35} \cdot 20\\\\y=\dfrac{8}{35} x^{2} +\dfrac{64}{35} x-\dfrac{160}{35} \\\\y=\dfrac{8}{35} x^{2} +1\dfrac{29}{35} x-4\dfrac{20}{35} \\\\\huge\boxed {~~y=\dfrac{8}{35} x^{2} +1\dfrac{29}{35} x-4\dfrac{4}{7} ~~}[/tex]
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Odpowiedź:
[tex]\huge\boxed {~~y=\dfrac{8}{35} x^{2} +1\dfrac{29}{35} x-4\dfrac{4}{7} ~~}~~\Rightarrow[/tex] wzór szukanej funkcji kwadratowej
Szczegółowe wyjaśnienie:
Korzystamy ze wzoru:
Rozwiązanie :
Dane z treści zadania:
Szukana:
Obliczamy :
[tex]y=a(x-x_{1} )(x-x_{2} )~~\land ~~x_{1} =-10~~\land~~x_{2} =2\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\Downarrow \\\\y=a(x-(-10) )(x-2)\\\\y=a(x+10 )(x-2)~~\land ~~A\in y~~\land ~~A(-3,-8)\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\Downarrow \\\\-8=a(-3+10)(-3-2)\\\\a\cdot 7\cdot (-5)=-8\\\\-35a=-8~~\mid \div (-35)\\\\\huge\boxed {~~a=\dfrac{8}{35} ~~}\\\\\\y=a(x+10)(x-2)~~\land ~~a=\dfrac{8}{35} \\\\~~~~~~~~~~~~~~~\Downarrow \\\\y=\frac{8}{35} (x^{2} -2x+10x-20)\\\\y=\frac{8}{35} (x^{2} +8x-20)\\[/tex]
[tex]y=\dfrac{8}{35} x^{2} +\dfrac{8}{35} \cdot 8x-\dfrac{8}{35} \cdot 20\\\\y=\dfrac{8}{35} x^{2} +\dfrac{64}{35} x-\dfrac{160}{35} \\\\y=\dfrac{8}{35} x^{2} +1\dfrac{29}{35} x-4\dfrac{20}{35} \\\\\huge\boxed {~~y=\dfrac{8}{35} x^{2} +1\dfrac{29}{35} x-4\dfrac{4}{7} ~~}[/tex]