Explicación:
•9.
•a)
•Em=Epg+Ec=m×g×h+(1/2)×m×V²=(80 kg)×(10 m/s²)×(5,2 m)+(1/2)×(80 kg)×(0 m/s)²=4.160 J.
•b)
•Em=Epg+Ec=m×g×h+(1/2)×m×V²=(80 kg)×(10 m/s²)×(0 m)+(1/2)×(80 kg)×(5 m/s)²=1.000 J.
•J=julio=joule.
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Verified answer
Explicación:
•9.
•a)
•Em=Epg+Ec=m×g×h+(1/2)×m×V²=(80 kg)×(10 m/s²)×(5,2 m)+(1/2)×(80 kg)×(0 m/s)²=4.160 J.
•b)
•Em=Epg+Ec=m×g×h+(1/2)×m×V²=(80 kg)×(10 m/s²)×(0 m)+(1/2)×(80 kg)×(5 m/s)²=1.000 J.
•J=julio=joule.