Porównaj zawartość procentowy wodoru w HCL i H2S.DUZO PUNKTOW PROSZE O POMOC
mcz HCl = 36,5u
36,5u - 100%
1u - x
--------------
x=2,74%
mczH2S=34u
34u-100%
2u -x
---------------
x=5,88%
36,5 g HCl - 100%
1g H - x%
x=2,74% H
M H2S= (2*1) +32 = 34g/mol
34g H2S -100%
2g H -x %
x=5,88% H
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mcz HCl = 36,5u
36,5u - 100%
1u - x
--------------
x=2,74%
mczH2S=34u
34u-100%
2u -x
---------------
x=5,88%
36,5 g HCl - 100%
1g H - x%
x=2,74% H
M H2S= (2*1) +32 = 34g/mol
34g H2S -100%
2g H -x %
x=5,88% H