Respuesta:
Explicación:
6KOH + 3Cl2 → KClO3 + 5KCl + 3H2O
a) calcular mol de KClO3
n KClO3 = 10 mol KOH x 1 mol KClO3
```````````````````````````
6 mol KOH
n KClO3 = 1.667 moles
b) calcular moles de cloro
n Cl2 = 5 mol KOH x 3 mol Cl2
`````````````````````````
n Cl2 = 2.5 moles
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Respuesta:
Explicación:
6KOH + 3Cl2 → KClO3 + 5KCl + 3H2O
a) calcular mol de KClO3
n KClO3 = 10 mol KOH x 1 mol KClO3
```````````````````````````
6 mol KOH
n KClO3 = 1.667 moles
b) calcular moles de cloro
n Cl2 = 5 mol KOH x 3 mol Cl2
`````````````````````````
6 mol KOH
n Cl2 = 2.5 moles