Respuesta:
Explicación paso a paso:
1. senФ = -6/10 <> -3/5
cosФ = 8/10 <> 4/5
tanФ = -6/8 <> -3/4
2. r² = (-√3)² + (-1)²
r² = 4
r = 2
Piden :
4senβ = 4(-1/2) <> -2
3. r² = (-1)² + 4²
r² = 1 + 16
r = √17
Piden : cos²θ = (-1/√17)² => 1/17
4. r² = 2² + 3²
r = √13
piden : senα . cosα = 3/√13 . 2/√13 => 6/13
Bueno se me cuida y recuerde tomar awa ;3
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Respuesta:
Explicación paso a paso:
1. senФ = -6/10 <> -3/5
cosФ = 8/10 <> 4/5
tanФ = -6/8 <> -3/4
2. r² = (-√3)² + (-1)²
r² = 4
r = 2
Piden :
4senβ = 4(-1/2) <> -2
3. r² = (-1)² + 4²
r² = 1 + 16
r = √17
Piden : cos²θ = (-1/√17)² => 1/17
4. r² = 2² + 3²
r = √13
piden : senα . cosα = 3/√13 . 2/√13 => 6/13
Bueno se me cuida y recuerde tomar awa ;3