Respuesta:
75
Explicación paso a paso:
[tex]\frac{x-2}{3}+\frac{x-1}{4} = 6\frac{2}{3} \\\\\frac{4(x-2) + 3(x-1)}{12} = \frac{20}{3} \\\\\frac{4x-8+3x-3}{12} = \frac{20}{3} \\\\\frac{x-5}{12} =\frac{20}{3}\\\\\{3x-15} = \frac{20}{3} \\\\{3x} = {225}\\\\{x} = {\frac{225}{3} }\\\\{x} = {75}[/tex]
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Respuesta:
75
Explicación paso a paso:
[tex]\frac{x-2}{3}+\frac{x-1}{4} = 6\frac{2}{3} \\\\\frac{4(x-2) + 3(x-1)}{12} = \frac{20}{3} \\\\\frac{4x-8+3x-3}{12} = \frac{20}{3} \\\\\frac{x-5}{12} =\frac{20}{3}\\\\\{3x-15} = \frac{20}{3} \\\\{3x} = {225}\\\\{x} = {\frac{225}{3} }\\\\{x} = {75}[/tex]