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pH = - Log[H⁺]
Q = -log[3 x 10⁻²]
Q = -(-1.52) = 1.52
R = -log[ 1 x 10⁻⁶]
R = -(-6) = 6
S = -log[ 4 x 10⁻³]
S = -(-2.39) = 2.39
T = -log[ 2 x 10⁻⁴]
T = -(-3.7) = 3.7
AHORA PUEDES RESPODER TUS PREGUNTAS