Question

por favor es para hoy con resolución

Answer 1

Respuesta:

            [tex]7[/tex]

Explicación paso a paso:

Por Pitágoras.

[tex](Hipotenusa)^{2} = (cateto.1)^{2} + (cateto.2)^{2}[/tex]

[tex](2\sqrt{5} )^{2} = (x+1)^{2} +(x-1)^{2}[/tex]

[tex]4(5) = x^{2} +2(x)(1)+1^{2} + x^{2} -2(x)(1)+1^{2}[/tex]

[tex]20 = x^{2} +2x+1+x^{2} -2x+1[/tex]

[tex]20 = 2x^{2} +2[/tex]

[tex]20-2= 2x^{2}[/tex]

[tex]18=2x^{2}[/tex]

[tex]\frac{18}{2} = x^{2} x^{2}[/tex]

[tex]9 = x^{2}[/tex]

[tex]\sqrt{9} = x[/tex]

[tex]x = 3[/tex]

[tex]Sec(O) = \frac{Hipotenusa}{Cateto-adyacente} = \frac{2\sqrt{5} }{x-1} =\frac{2\sqrt{5} }{3-1}[/tex]

[tex]Sec(O) = \frac{2\sqrt{5} }{2} = \sqrt{5}[/tex]

[tex]Cot(O )= \frac{Cateto-adyacente}{Cateto-opuesto} =\frac{x-1}{x+1} =\frac{3-1}{3+1} =\frac{2}{4} = \frac{1}{2}[/tex]

[tex]Cot(O) = \frac{1}{2}[/tex]

[tex]F = \sqrt{5} Sec(O)+4Cot(O)[/tex]

[tex]F = \sqrt{5} *(\sqrt{5} )+4(\frac{1}{2} ) = \sqrt{25} +\frac{4}{2} = 5+2[/tex]

[tex]F = 7[/tex]