Por favor es para el lunes
hallar:a+b+c,si:
(x+3)(2x-5)=ax∧2+b+cx
hallar:a+b+c,si:
(x+3)(2x-5)=ax∧2+b+cx
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2x² - 5x + 6x - 15
2x² + x - 15
El resultado lo igualamos a ax² + cx + b
2x² + 1 x - 15 = a x² + c x + b
de donde a= 2
c = 1
b = -15
a + b + c = 2 + -15 + 1 = - 12⇒ Respuesta