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A=[x∈N/x es impar x<7 ]
A={1,3,5}
B={x∈N/x es par y x<6 }
B={0,2,4}
C={x∈N/x es primo y x<7 }
C={2,3,5}
Entonces :
a. A∪B={1,3,5] .... (F)
b.A∩B={1,3}.....(F)
c.A∪B∪C={2,3,5}....(F)
d. B∩C={2} .... (V)
Respuesta: D
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