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Nos que da 8 x = 3 y^3. Explicitamos en y:
y = (8/3 x)^(1/3)
Derivamos: y ' = 1/3 (8/3 x)^(- 2/3) . 8/3 = 8/9 . 1 / (8/3 x)^(2/3)
Saludos Herminio