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2) x-y+z=60
3) -x+y+z=100
metodo eliminacion
x+y-z=20
x-y+z=60
sumando
2x+0+0=80
x=80/2
x=40
2) x-y+z=60
3) -x+y+z=100
x-y+z=60
-x+y+z=100
sumando
0+0+2z=160
z=160/2
z=80
reemplazondo x y z en 1) tenemos que
1) 40+y-80=20
y=20-40+80
y=60
por favor espero tus gracias