Odpowiedź:
z.1
a = 12
h = [tex]a*\frac{\sqrt{3} }{2} = 6 \sqrt{3}[/tex]
I AS I = [tex]\frac{2}{3} *h = 4\sqrt{3}[/tex]
I AW I = a = 12
I SW I² = 12² - ( 4√3)² = 144 - 48 = 96 = 16*6
I SW I = 4 √6
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Odpowiedź:
z.1
a = 12
h = [tex]a*\frac{\sqrt{3} }{2} = 6 \sqrt{3}[/tex]
I AS I = [tex]\frac{2}{3} *h = 4\sqrt{3}[/tex]
I AW I = a = 12
I SW I² = 12² - ( 4√3)² = 144 - 48 = 96 = 16*6
I SW I = 4 √6
Szczegółowe wyjaśnienie: