Odpowiedź:
Pb = 207 g/mol C = 12g/mol H = 1 g/mol
Pb(C2H5)4 => C= 12g*8 = 96g H = 1g*20 = 20g= 96g+20g+207g = 323 g/mol
323g --- 100%
207g ---- x%
x = 64% => Pb = 64% .
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Odpowiedź:
Pb = 207 g/mol C = 12g/mol H = 1 g/mol
Pb(C2H5)4 => C= 12g*8 = 96g H = 1g*20 = 20g= 96g+20g+207g = 323 g/mol
323g --- 100%
207g ---- x%
x = 64% => Pb = 64% .
Wyjaśnienie: