Question

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Answer 1

a) SO2=32u+2*16u=64u

b) HNO3 =1u+14u+3*16u=63u

c) H2SO4=2*1u+32u+4*16u=98u

d) Ba(OH)2=137u+2*16u+21u=171u

e) Na2S=2*23u+32u=78 u

f) Pb3(PO4)2=3*207u+2*31u+8*16u=811u

g) C3H7COOH=4*12u+8*1u+2*16u=88u

Answer 2

Odpowiedź:

mSO2= 32u+ 2× 16u= 32u+ 32u= 64u

mHNO3= 1u+ 14u+ 3× 16u= 1u+14u + 48u= 63u

mH2SO4= 2× 1u+ 32u+ 4× 16u= 2u+ 32u+ 64u= 98u

mBa(OH)2=137u+ 2× ( 16u+ 1u)=137u + 2× 17u= 137u+ 34u= 171u

mNa2S= 2× 23u+ 32u= 46u+ 32u= 78u

mPb3(PO4)2=3× 207u+ 2×( 31u+ 4×16u)= 621u+ 2×( 31u+ 64u)= 621u+2× 95u= 621u+ 190u= 811u

mC3H7COOH= 3× 12u+ 7× 1u+ 12u+ 16u+ 16u+ 1u= 36u+ 7u+ 12u+ 16u+ 16u+ 1u= 88u

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