Odpowiedź:
z,1
1 ,2,3,5,6,7 ( 3 + 5) : 2 = 4
Odp. B 4
============
z.2
1 ,1,1,2,3,4,5,5
Odp. A 1
=============
z.3
1,3,3,4,4
x = ( 1 + 2*3 + 2*4 ) : 5 = 15 : 5 = 3
ρ² = [tex]\frac{(1 - 3)^2 + 2*(3 - 3)^2 + 2*(4 - 3 )^2}{5} = \frac{4 + 2}{5} = \frac{6}{5} = 1,2[/tex]
ρ = [tex]\sqrt{1,2}[/tex]
Odp. B
========
z.4
( 1 + 3 + 5 + x + 4 + 2 + 6 + 2) : 8 = 3
więc
23 + x = 8*3 = 24
x = 24 - 23 = 1
Odp, B x = 1
==================
z.5
1,3, x, y, 6, 7
Jest 1, 3,3,4,6,7 bo ( 3 + 4) : 2 = 3,5 oraz d = 3
Odp. A x = 3 , y = 4
=========================
z.6
1 , 4,x, y, 6
Mamy 1,4, 4,5,6 bo d = 4 oraz x = ( 1 + 2*4 + 5 + 6) : 5 = 4
Odp. C x = 4, y = 5
z.7
3,4,x,y, 7, 9
Mamy 3, 4 6, 7,7, 9 bo x = ( 3 + 4 + 6 + 2*7 + 9 ) : 6 = 36 : 6 = 6
oraz ( 6 + 7 ) : 2 = 6,5
Odp. D x = 6 y = 7
=======================
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Odpowiedź:
z,1
1 ,2,3,5,6,7 ( 3 + 5) : 2 = 4
Odp. B 4
============
z.2
1 ,1,1,2,3,4,5,5
Odp. A 1
=============
z.3
1,3,3,4,4
x = ( 1 + 2*3 + 2*4 ) : 5 = 15 : 5 = 3
ρ² = [tex]\frac{(1 - 3)^2 + 2*(3 - 3)^2 + 2*(4 - 3 )^2}{5} = \frac{4 + 2}{5} = \frac{6}{5} = 1,2[/tex]
ρ = [tex]\sqrt{1,2}[/tex]
Odp. B
========
z.4
( 1 + 3 + 5 + x + 4 + 2 + 6 + 2) : 8 = 3
więc
23 + x = 8*3 = 24
x = 24 - 23 = 1
Odp, B x = 1
==================
z.5
1,3, x, y, 6, 7
Jest 1, 3,3,4,6,7 bo ( 3 + 4) : 2 = 3,5 oraz d = 3
Odp. A x = 3 , y = 4
=========================
z.6
1 , 4,x, y, 6
Mamy 1,4, 4,5,6 bo d = 4 oraz x = ( 1 + 2*4 + 5 + 6) : 5 = 4
Odp. C x = 4, y = 5
=========================
z.7
3,4,x,y, 7, 9
Mamy 3, 4 6, 7,7, 9 bo x = ( 3 + 4 + 6 + 2*7 + 9 ) : 6 = 36 : 6 = 6
oraz ( 6 + 7 ) : 2 = 6,5
Odp. D x = 6 y = 7
=======================
Szczegółowe wyjaśnienie: