Question

Pomoże ktoś w tych obliczeniach? Klasa7
daję naj
ZADANIE 7

Answer 1

Odpowiedź:

Szczegółowe wyjaśnienie:

a)

2/3 * (2 5/6 + 1,75) = 2/3 * ( 2 5/6 + 1 3/4) = 2/3 * (2 10/12 + 1 9/12) =

= 2/3 * 4 7/12 = 2/3 * 55/12 = 1/3 * 55/6 = 55/18 = 3 1/18

b)

(4 7/8 - 2,5) * 1 1/3 = (4 7/8 - 2 1/2) * 1 1/3 = (4 7/8 - 2 4/8) * 1 1/3 = 2 3/8 * 1 1/3 = 19/8 * 4/3 = 19/2 * 1/3 = 19/6 = 3 1/6

c)

2 2/3 : (1 7/9 + 2 2/15) = 2 2/3 : (1 35/45 + 2 6/45) = 2 2/3 : 3 41/45 =

= 8/3 : 176/45 = 8/3 * 45/176 = 1 * 15/22 = 15/22

d)

1 4/5 : (8 13/25 - 1,5) = 1,8 : (8,52 - 1,50) = 1,8 : 7,02 = 1 4/5 : 7 1/50 =

= 9/5 : 351/50 = 9/5 * 50/351 = 1 * 10/39 = 10/39

e)

3 1/2 * (1 3/5 + 2,75) = 3,5 * (1,60 + 2,75) = 3,5 * 4,35 = 3 1/2 * 4 7/20 =

= 7/2 * 87/20 = 609/40 = 15 9/40

f)

1 2/3 : (5,5 * 2 2/11 - 3 2/3) = 1 2/3 : ( 11/2 * 24/11 - 3 2/3) =

= 1 2/3 : (1/2 - 3 2/3) = 1 2/3 : ( 3/6 - 3 4/6) = 1 2/3 : ( 3/6 - 2 10/6) =

= 1 2/3 : 2 7/6 = 1 2/3 : 3 1/6 = 5/3 : 19/6 = 5/3 * 6/19 = 5 * 2/19 = 10/19