Pomnożyć obustronnie przez sześć, wtedy
[tex] \frac{6(x + 1)}{3} = \frac{6(x - 1)}{2} [/tex]
[tex] \frac{6}{3} (x + 1) = \frac{6}{2} (x - 1)[/tex]
[tex]2(x + 1) = 3(x - 1)[/tex]
[tex]2x + 2 = 3x - 3[/tex]
-x = -5 / :(-1)
x = 5
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Verified answer
Pomnożyć obustronnie przez sześć, wtedy
[tex] \frac{6(x + 1)}{3} = \frac{6(x - 1)}{2} [/tex]
[tex] \frac{6}{3} (x + 1) = \frac{6}{2} (x - 1)[/tex]
[tex]2(x + 1) = 3(x - 1)[/tex]
[tex]2x + 2 = 3x - 3[/tex]
-x = -5 / :(-1)
x = 5