Matematika
Nomor 6
f(x) = ax + b
x² - 1 = (x - 1)(x + 1)
x = 1
g(1) = a + b
3 = a + b
x = -1
g(-1) = -a + b
2 = -a + b
Eliminasi
a + b = 3
-a + b = 2
__________-
2a = 1
a = ½
Substitusi
b = 3 - ½
b = 5/2
g(x) = ax + b
= (½)x + 5/2
h(x) = a + b
1 = a + b
h(-1) = -a + b
a + b = 1
2a = -1
a = - ½
Subtitusi
b = 1 + ½
b = 3/2
h(x) = ax + b
= (-½)x + 3/2
f(x) = g(x) / h(x)
= ( (½)x + 5/2 ) / ( (-½)x + 3/2) (masing² ×2)
= (x + 5) / (-x + 3)
f(1) = (1 + 5) / (-1 + 3)
= 6 / 2
= 3
f(-1) = (-1 + 5) / (-(-1) + 3)
= 4 / 4
= 1
f(1) = a + b
f(-1) = -a + b
1 = -a + b
-a + b = 1
2a = 2
a = 1
subtitusi
b = 3 - 1
b = 2
= x + 2
jawaban A
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jawaban lainnya :
3). A. x-2
4). D. 2x+5
5). C. 12x-3
Matematika
Nomor 6
f(x) = ax + b
x² - 1 = (x - 1)(x + 1)
x = 1
g(1) = a + b
3 = a + b
x = -1
g(-1) = -a + b
2 = -a + b
Eliminasi
a + b = 3
-a + b = 2
__________-
2a = 1
a = ½
Substitusi
a + b = 3
b = 3 - ½
b = 5/2
g(x) = ax + b
= (½)x + 5/2
x = 1
h(x) = a + b
1 = a + b
x = -1
h(-1) = -a + b
2 = -a + b
Eliminasi
a + b = 1
-a + b = 2
__________-
2a = -1
a = - ½
Subtitusi
a + b = 1
b = 1 + ½
b = 3/2
h(x) = ax + b
= (-½)x + 3/2
f(x) = g(x) / h(x)
= ( (½)x + 5/2 ) / ( (-½)x + 3/2) (masing² ×2)
= (x + 5) / (-x + 3)
f(x) = ax + b
f(1) = (1 + 5) / (-1 + 3)
= 6 / 2
= 3
f(-1) = (-1 + 5) / (-(-1) + 3)
= 4 / 4
= 1
f(x) = ax + b
f(1) = a + b
3 = a + b
f(-1) = -a + b
1 = -a + b
Eliminasi
a + b = 3
-a + b = 1
__________-
2a = 2
a = 1
subtitusi
a + b = 3
b = 3 - 1
b = 2
f(x) = ax + b
= x + 2
jawaban A