" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
cl = 2100 J/kg * C
ct = 334000 J/kg
t₁ = - 10 C
t₂ = 0 C
t₃ = 90 C
cw = 4200 J/kg * C
Q = Q₁ + Q₂ + Q₃
1. ogrzanie lodu do temp. topnienia : Q₁
Q₁ = m * cl * ( t₂ - t₁ )
Q₁ = 5 kg *2100 J/kg * C * [ 0 C - ( -10 C )]
Q₁ = 105000 J = 105 kJ
2. stopienie lodu : Q₂
Q₂ = m *ct
Q₂ = 5 kg * 334000 J/kg
Q₂ = 1670000 J = 1670 kJ
3. ogrzanie wody powstałej ze stopienia lodu : Q₃
Q₃ = m * cw * ( t₃ - t₂ )
Q₃ = 5 kg * 4200 J/kg * C * ( 90 C - 0 C) = 1980000 J = 1890 kJ
4. całkowita energia :
Q = Q₁ + Q₂ + Q₃
Q = 1775 kJ ≈ 1,8 MJ
1 MJ = 10⁶ J