Odpowiedź:
Cz=4020 pF
C1 = 3,9nF = 3900 pF
Cz = C1+C2
C2 = Cz-C1 = 4020 - 3900 = 120 pF
odp. a) 120 pF
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Odpowiedź:
Cz=4020 pF
C1 = 3,9nF = 3900 pF
Cz = C1+C2
C2 = Cz-C1 = 4020 - 3900 = 120 pF
odp. a) 120 pF
Wyjaśnienie: