0,000009/°C
Penjelasan:
Lo = 1 m = 100 cm
Lt = 100,072 cm
∆L = 100,072 - 100
= 0,072 cm
∆T = 120 - 40 = 80°C
∆L = Lo x c x ∆T
c = ∆L : (Lo x ∆T)
= 0,072 : (100 x 80)
= 0,072 : 8.000
= 0,000009/°C
∆L = Lo x c x ∆t
c = ∆L ÷ (Lo x ∆t)
c = 0,072 ÷ ( 100 x 80)
c = 0,072 ÷ 8000
c = 0,000009/° c
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0,000009/°C
Penjelasan:
Lo = 1 m = 100 cm
Lt = 100,072 cm
∆L = 100,072 - 100
= 0,072 cm
∆T = 120 - 40 = 80°C
∆L = Lo x c x ∆T
c = ∆L : (Lo x ∆T)
= 0,072 : (100 x 80)
= 0,072 : 8.000
= 0,000009/°C
Penjelasan:
∆L = Lo x c x ∆t
c = ∆L ÷ (Lo x ∆t)
c = 0,072 ÷ ( 100 x 80)
c = 0,072 ÷ 8000
c = 0,000009/° c