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Verified answer
Y= ⅔ x + 9=⅔
Syarat tegak lurus
x = -1
⅔ x = -1
= ⁻³/₂
y - = m ( x - )
y + 3 = ⁻³/₂ (x + 2) [ kalikan -2 kedua ruas)
-2y - 6 = 3 (x + 2)
3x + 6 + 2y + 6 = 0
3x + 2y + 12 = 0