Question

Tolong bantu ya, terima kasih :)

A. Tentukan pH dari konsentrasi larutan H+ dan OH- dibawah ini!
1.) H+ 0,0001 M
2.) OH- 0,002 M
3.) OH- 0,03 M

B. Tentukan konsentrasi H+ dari pH/pOH dibawah ini!
1.) pH = 10
2.) pOH = 4
3.) pOH = 2 + log2

Answer 1

1) pH = -log0,0001 = 4
2) pOH = -log0,002 = 2.7
pH = 14-2.7 = 11.3
3) pOH = -log0,03 = 1.52
pH = 14-1.52 = 12.48

1) pH = 10
H+ = 1 x 10^-10
2) pOH = 4
pH = 10
H+ = 1 x 10^-10
3) pOH = 2 + log2
pH = 14-2+log2 = 12 + log 2 = 12.3

Answer 2

B.1.pH=10
-log[H⁺]=-log 1 x 10⁻¹⁰ (-log sama sama dicoret)
[H⁺]=1 x 10⁻¹⁰
2.pOH=4
pH=14-4
pH=10
-log[H⁺]=-log1 x 10⁻¹⁰ (-log dicoret)
[H⁺]=1 x 10⁻¹⁰
3.pOH=2+log 2
pH=14-(2+log2)
pH=12-log 2
-log [H⁺]=-log 2 x 10⁻¹² (-log dicoret
[H⁺]=2 x 10⁻¹²