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Caso.
Factor Comun.
3a³ + 24a²b + 48ab² = Sacas factor comun 3a
3a(a² + 8ab + 16b²) = El parentesis es un trinomio al cuadrado perfec.
aplicas a² + 2ab + b² = (a + b)²
3a(a² + 2(a)(4) + 4²b²) =
3a(a + 4b)²
Respuesta.
3a(a + 4b)²