Podaj wzór sumaryczny estru o masie 102u. PROSZĘ O WYJAŚNIENIE
Ester: Octan propylu
CH3-C00-CH2-CH2-CH3
Bo: C=12 H=1 O=16 12*5 + 1*10 + 2*16 = 102
HCOOC4H9 -
10H - 10u
5C - 60u
2O - 32u
10 + 60 + 32 = 102u
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Ester: Octan propylu
CH3-C00-CH2-CH2-CH3
Bo: C=12 H=1 O=16
12*5 + 1*10 + 2*16 = 102
HCOOC4H9 -
10H - 10u
5C - 60u
2O - 32u
10 + 60 + 32 = 102u