Question

Podaj w masie cząsteczkowej:
mH20=
mS8=
mCO2=
mNH3=
mH3PO4=
mH2SO4=
mCUCO3=
mKNO3=

Answer 1

a) mH₂O = 2*1u+16u = 18 u
b) mS₈ = 8×32u = 256 u
c) mCO₂ = 12u+2*16u = 44 u
d) mNH₃ = 14u+3*1u = 17 u
e) mH₃PO₄ = 3*1u+31u+4*16u = 98 u
f) mH₂SO₄ = 2*1u+32u+4*16u = 98 u
g) mCuCO₃ = 64u+12u+3*16u = 124 u
h) mKNO₃ = 39u+14u+3*16u = 101 u