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t ker = 31-7 = 24 cm
s = 25 (dgn triple Pythagoras)
luas bandul = luas setengah bola + luas selimut kerucut
= 2πr² + πrs
= πr(2r+s)
= 22/7×7×(2.7+25)
= 22×(14+25)
= 22×39
= 858 cm²