Question

PLSV
Sebuah persegipanjang, panjangnya 10 cm dan lebarnya (a-3) cm. Luasnya 60cm². Tentukan lebar persegipanjang itu!

Answer 1

Luas = panjang x lebar
60 = 10 x (a-3)
60 = 10(a-3)
60 = 10a - 30
60 + 30 = 10a -30 + 30
90 = 10a
90 : 10 = a
9 = a

lebar = a - 3
lebar = 9 - 3 = 6 cm

Answer 2

Lprsgi pnjng= p * l
60 = 10 * (a-3)
60= 10 a -30
60+30 = 10 a
90 = 10 a
90 /10 = a
9 = a

jdi lebarnya a-3 = 9-3 = 6