m = 5 kg
F = ma
mgsin60° = ma
(5)(10)(1/2 √3) = (5)a
25√3 = 5a
a = 5√3
F = 25 √3 = ma
Usaha = F × s
= 25√3 × 5
= 125√3 J
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m = 5 kg
F = ma
mgsin60° = ma
(5)(10)(1/2 √3) = (5)a
25√3 = 5a
a = 5√3
F = 25 √3 = ma
Usaha = F × s
= 25√3 × 5
= 125√3 J