Odpowiedź:
zad 1
2/10, 4/10, 5/10, 18/10 = 1 i 8/10, 1 i 4/10, 18/10 = 1 i 8/10
to zaznacz na osi liczbowej
zad 2
1/2 = 2/4 = 8/16
24/8 = 3
2 i 1/3 = 2 i 2/6 = 14/6
28/8 = 3 i 4/8 = 3 i 1/2
1 i 6/8 = 1 i 3/4
3 i 7/3 = 5 i 1/3
22/7 = 3 i 1/7
zad 3
1 i 4/8 + 5/8 = 1 i 9/8 = 2 i 1/8
3 i 2/7 : 5 = 23/7 * 1/5 = 23/35
12 i 1/4 - 10 i 3/6 = 12 i 3/12 - 10 i 6/12 = 11 i 15/12 - 10 i 6/12 = 1 i 9/12 = 1 i 3/4
2 i 3/4 + 2 i 7/8 = 2 i 6/8 + 2 i 7/8 = 4 i 13/8 = 5 i 5/8
10 - 6 i 1/3 - 9 i 3/3 - 6 i 1/3 = 3 i 2/3
4 i 2/5 : 1 i 1/10 = 22/5 * 10/11 = 4
4 i 2/6 * 6 = 26/6 * 6 = 26
zad 4
22 - (3 i 1/2 * 2 + 4 i 3/4) = 22 - (7/2 * 2 + 4 i 3/4) = 22 - (7 + 4 i 3/4) = 22 - 11 i 3/4 = 21 i 4/4 - 11 i 3/4 = 10 i 1/4
4 i 2/3 : 2 + 4 i 2/5 * 5 = 14/3 * 1/2 + 22/5 * 5 = 7/3 + 22 = 22 i 7/3 = 24 i 1/3
zad 5
4/7 liczby 56 = 4/7 * 56 = 32
Znaleźli 32 prawdziwków
zad 6
12 km * 1/6 = 2 km ---- tyle jedzie rowerem
12 km * 2/3 = 8 km ---- tyle jedzie autobusem
12 km - (2 km + 8 km) = 12 - 10 = 2 km --- tyle idzie piechotą
zad 7
2 i 1/4 --- tyle zebrała Ania
2 i 1/4 + 1/2 = 2 i 1/4 + 2/4 = 2 i 3/4 ---- tyle zebrała Kasia
2 i 3/4 - 5/8 = 2 i 6/8 - 5/8 = 2 i 1/8 ---tyle zebrała Zosia
2 i 1/4 + 2 i 3/4 + 2 i 1/8 = 2 i 2/8 + 2 i 6/8 + 2 i 1/8 = 6 i 9/8 = 7 i 1/8 ----tyle zebrały razem
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Odpowiedź:
zad 1
2/10, 4/10, 5/10, 18/10 = 1 i 8/10, 1 i 4/10, 18/10 = 1 i 8/10
to zaznacz na osi liczbowej
zad 2
1/2 = 2/4 = 8/16
24/8 = 3
2 i 1/3 = 2 i 2/6 = 14/6
28/8 = 3 i 4/8 = 3 i 1/2
1 i 6/8 = 1 i 3/4
3 i 7/3 = 5 i 1/3
22/7 = 3 i 1/7
zad 3
1 i 4/8 + 5/8 = 1 i 9/8 = 2 i 1/8
3 i 2/7 : 5 = 23/7 * 1/5 = 23/35
12 i 1/4 - 10 i 3/6 = 12 i 3/12 - 10 i 6/12 = 11 i 15/12 - 10 i 6/12 = 1 i 9/12 = 1 i 3/4
2 i 3/4 + 2 i 7/8 = 2 i 6/8 + 2 i 7/8 = 4 i 13/8 = 5 i 5/8
10 - 6 i 1/3 - 9 i 3/3 - 6 i 1/3 = 3 i 2/3
4 i 2/5 : 1 i 1/10 = 22/5 * 10/11 = 4
4 i 2/6 * 6 = 26/6 * 6 = 26
zad 4
22 - (3 i 1/2 * 2 + 4 i 3/4) = 22 - (7/2 * 2 + 4 i 3/4) = 22 - (7 + 4 i 3/4) = 22 - 11 i 3/4 = 21 i 4/4 - 11 i 3/4 = 10 i 1/4
4 i 2/3 : 2 + 4 i 2/5 * 5 = 14/3 * 1/2 + 22/5 * 5 = 7/3 + 22 = 22 i 7/3 = 24 i 1/3
zad 5
4/7 liczby 56 = 4/7 * 56 = 32
Znaleźli 32 prawdziwków
zad 6
12 km * 1/6 = 2 km ---- tyle jedzie rowerem
12 km * 2/3 = 8 km ---- tyle jedzie autobusem
12 km - (2 km + 8 km) = 12 - 10 = 2 km --- tyle idzie piechotą
zad 7
2 i 1/4 --- tyle zebrała Ania
2 i 1/4 + 1/2 = 2 i 1/4 + 2/4 = 2 i 3/4 ---- tyle zebrała Kasia
2 i 3/4 - 5/8 = 2 i 6/8 - 5/8 = 2 i 1/8 ---tyle zebrała Zosia
2 i 1/4 + 2 i 3/4 + 2 i 1/8 = 2 i 2/8 + 2 i 6/8 + 2 i 1/8 = 6 i 9/8 = 7 i 1/8 ----tyle zebrały razem