Jawab:
B. 2090
Penjelasan dengan langkah-langkah:
Luas permukaan kerucut = π×r×(r+s) = 22/7 × 7 × (7 + 10) = 22×17 = 374cm(Jari-jari = 14÷2 = 7)Luas permukaan tabung = 2×π×r×(r+t) = 2×22/7×7×(7+32) = 2×22×39 = 1.716cmLuas permukaan gabungan = 374 + 1.716 = 2.090
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Jawab:
B. 2090
Penjelasan dengan langkah-langkah:
Luas permukaan kerucut = π×r×(r+s) = 22/7 × 7 × (7 + 10) = 22×17 = 374cm
(Jari-jari = 14÷2 = 7)
Luas permukaan tabung = 2×π×r×(r+t) = 2×22/7×7×(7+32) = 2×22×39 = 1.716cm
Luas permukaan gabungan = 374 + 1.716 = 2.090